FREE MockTest

Register Now       Login

Home | Colleges | Entrance Exams | Downloads | News | Opinion  | Blogs |Contact Us

Blog Question

Subject:two particles a and b start moving simultaneously along the line....

Query:

two particles a and b start moving simultaneously along the line joining them in the same direction with acceleration of 1m/s^2 and 2m/s^2 and speeds 3m/s and 1m/s respectively.initially,a is 10m behind b.what is the minimum distance between them.

ans-8 m.

Name:nilesh
Date:03 Mar 2009
Score: 0
Reply

Most Recent comment
 


 

distance traveled by particle 'a' (s1)

s1=u1*t +1/2 *a1*t2

s1=3*t + t2 / 2

distance traveled by particle 'b'(s2)

s2= u2 *t + 1/2*a2*t2

s2= t + t2

s1 - s2= 2t-t2/2

Minimizing s1 - s2 differentiate  the above equation and equate it with zero

we get t=2sec

put the value of t in s1 and s2 and get the required distance

Name : honey
Date  :07 Mar 2009
Score  :10

Post Your Reply/Comments
Name
Email id  
Reply

 
Home News Contact Us Blogs Downloads colleges Registration Entrance Exams
Indiaiit.com NewsLetter For Exclusive News Letter
www.Indiapmt.com we care for your Career
          www.indiacats.com   Grab The Mouse Bell The CAT
www.indiaspaces.com  spaces to fill your life
Design and developed by Innovations Computech Pvt.Ltd