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Subject:pls answer-a particle is projected at an angle of 60 degree with the horizontal with a speed

Query:

a particle is projected at an angle of 60 degree with the horizontal with a speed 20m/s,taking g=10 m/s^2,find the time after which the speed of the particle remains half of initial speed.

ans-root 3 seconds.
Name:nilesh
Date:03 Mar 2009
Score: 0
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Date:07 Mar 2009

Subject: pls answer-a particle is projected at an angle of 60 degree with the horizontal with a speed

Reply

let required time be t sec.

speed in horizontal direction(v1)=20m/s.

speed in vertical direction(v2)= gt  =10t

total speed=root(v1*v1 + v2*v2)

total speed= v1 / 2 = 20/2=10m/s

10=root(400+100*t*t)

hence t=root(3)sec

Name : ravi
Date  :07 Mar 2009
Score  :10


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